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Mar-13-18 | | stacase: This required a bit of chin stroking and remembering how to count, but it wasn't as bad as yesterday that said it was Black's move when Black was on life support. When I tuned back in to see what Black did, he moved his King. Somewhere in that confusion I realized Chessgames.com zigged instead of zagged. Oh well. <Phony Benoni...winning the resulting Q vs. R ending is not as easy as everybody thinks, but that's not my problem.>
Ha ha ha (-: |
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Mar-13-18
 | | gawain: Because this was a puzzle position (and "easy") the solution could not possibly be anything other than 52 Rxh4+ etc. |
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Mar-13-18 | | lost in space: Got that and saw that the game went exactly to the position I had in my mind when starting to write my post. |
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Mar-13-18 | | ChessHigherCat: I saw the rook exchange and c6 almost instantly but yesterday's puzzle made me paranoid so I started looking for a faster solution |
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Mar-13-18 | | Pchief: Was the R sac really necessary?
If 52.Rg7 Black also does not have any useful move at hand since his king, not being able to leave the h-file, continues to block his own pawn |
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Mar-13-18 | | landshark: R sac brings the fastest resolution. |
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Mar-13-18 | | EIDorado: @Pchief with a single black rook on the board the king values as much as a night, so white has a knight and a pawn for the rook. Considering the active passed pawns and passive black king, you don't even check ending theory or variants: you just say to yourself "If white doesn't win I quit chess". |
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Mar-13-18 | | agb2002: White is a pawn up.
Black threatens Rxb7.
White's advanced pawns can overwhelm the rook on b8. Hence, 52.Rxh4+ Rxh4 53.Rxh4+ Kxh4 54.c6 followed by Kc5 wins (54... Kg5 55.Kc5 Kf6 56.Kd6 Rd8+ 57.Kc7 Ke7 58.b8=Q Rxb8 59.Kxb8 Kd6 60.c7). |
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Mar-13-18 | | yadasampati: I am just surprised that Levon Aronian does not resign after 52) Rxh4+ |
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Mar-13-18 | | Lambda: <Pchief> It probably isn't necessary, but simplifying complex wins into simple wins is always nice. |
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Mar-13-18 | | AlicesKnight: Simplest here is best; two Ps on the 6th defeat a R in the absence of Ks. So exchange everything on h4 and follow with c6; the Black R cannot hold. |
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Mar-13-18 | | morfishine: <52.Rxh4> eliminates one Black rook allowing the White King + 2 pawns to eliminate the other ***** |
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Mar-13-18
 | | OhioChessFan: Straightforward endgame, the Pawns dominate the Rook. I share yada's surprise Aronian played on. |
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Mar-13-18 | | Cheapo by the Dozen: After a Monday puzzle that was hard enough for Tuesday, we get a Tuesday puzzle that's Monday-easy. |
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Mar-13-18 | | cocker: 52 Rg7 also wins quite easily |
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Mar-13-18 | | WorstPlayerEver: Two connected pawns at the 6th rank can handle a Rook alone. |
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Mar-13-18
 | | Bubo bubo: White turns the double rook ending into an elementary win of two advanced passed pawns against a rook: 52.Rxh4+ Rxh4 53.Rxh4+ Kxh4 54.c6. Since his king is offside and the white king is close to the pawns, Black won't even reach the notorious Q vs R ending. |
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Mar-13-18 | | Mayankk: A refresher of basic Chess theory and not much of a puzzle. Is this week supposed to demonstrate how current/future 2800+ players miss simple stuff? |
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Mar-13-18 | | Pasker: An elementary puzzle of course but what surprised me is that Aronian is keep going after all this. I thought the game will be over right after the solution move but it goes on with Aronian's King march 😁 |
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Mar-13-18 | | lentil: In 1996, Aronian was 13 years old. |
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Mar-13-18 | | Pasker: Okay, I didn't realize it was 1996. Thought its 2013. That must be a very young Aronian. |
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Mar-13-18 | | takchess: Good basic instructive change of pace puzzle. This is position where the snarky annotator says: Every Russian School Child Knows..... |
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Mar-13-18 | | alwinkpc: How about this?
52. Rxh4+ Rxh4
53. c6 |
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Mar-13-18 | | Whitehat1963: Easier than yesterday’s. |
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Mar-13-18 | | patzer2: Finding the two connected pawns versus
Rook endgame in today's Tuesday (52. ?) puzzle was easy with the simplifying 52. Rxh4+ +-.For a possible improvement in this deeply analyzed and well know sicilian dragon opening, I prefer 14...Qc7 as in the drawn game Adams vs Nakamura, 2017. |
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