urtley has kibitzed 24 times to chessgames   [more...]

Sep-03-09 S Savchenko vs A Ivanov, 1991    urtley: dzechiel - for quite some time, yours are the only comments I read when failing to find the solution to these puzzles. Although today you did not post in depth, I still wanted to say keep up the good work.      Dec-27-05 Rublevsky vs Jakovenko, 2005    urtley: bf4 Qe6      Aug-04-05 C von Holstein-Rathlau vs H Kongsted, 2001    urtley: Kh1 looks losing... 32 Kh1 Rg1+ 33 RxR Qd5+ 34 Rg2 Qd1+! (35 RxQ RxR++) 35 Rg1 Bd5++. I'm at work, so I do not have as much time as i'd like to look at this position. Hopefully there are no errors      May-21-05 Topalov vs Ponomariov, 2005    urtley: ...Qc7# is not how it will end. ...Qd2+ Kf1 Bxc4 bxc Kh6 but then Bf4 and black can not escape      Nov-10-04 Mecking vs A C Rocha, 1969    urtley: ah yes...first post :) the mistake is 19...Qxb2      Oct-22-04 Gulko vs A Volovich, 1968    urtley: 1.7 seconds...must have had a stopwatch on you - good job. I think if 28 ... Kd8 29 Qf8+ fails to 29 ... Kc7 30 Rxe7+ Kb8 and the king is safe but black has nothing going for him :p      Sep-18-04 Vitacek vs Duras, 1900    urtley: <amdocs> I dont see 27Qc3+ being playable anywhere except for the line <23 ... Nb3+ 24 Pxb3 Bxb2+ (if 25 Kc2 Qxb3++)> where black can ALSO mate with Qc3++ as <Shadout Mapes> pointed out Going on with 29. Kc3 Bxd1+ (must be played to force the king onto the fourth ...      Sep-16-04 Chiburdanidze vs M Sharif, 1995    urtley: I do not see how 22. Bh3 merits resignation by black. If 22 ... Bxh3 23 Qg5+ Kh7 black is in the clear - any check on the h-file by white's queen can be blocked by black's bishop and defended on the next move; example: 24 Qh4+ Bh6 25 Bg5 Qe6 and what cannot even win back the bishop ...      Sep-12-04 Nunn vs Sadler, 1993    urtley: <Eggman> if 27 ... Rxf4 then 28 Rf1 giving the threat of Rh8+ and mate soon to follow since the king will interpose on its own rook.      Sep-10-04 Krasenkow vs Adianto, 1998    urtley: Nice play by white. if ... PxN then QxB++ or if ... NxQ then Nc7++

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