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Sam Loyd vs Jules Arnous de Riviere
Paris (1867), Paris FRA, Jun-04
Italian Game: Giuoco Pianissimo (C50)  ·  0-1

ANALYSIS [x]

FEN COPIED

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sac: 45...Nf3+ PGN: download | view | print Help: general | java-troubleshooting

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Kibitzer's Corner
Aug-15-06  Kwesi: I wonder if 48.Nxg3 would win for white?
Aug-15-06
Premium Chessgames Member
  Honza Cervenka: <Kwesi: I wonder if 48.Nxg3 would win for white?> No, it would not. If 48.Nxg3, then 48...Rh2+ 49.Re2 (else Kxe8) 49...fxe2 50.Nxe2 Ke6 with probable draw. On the other hand it was definitely better than 48.Re1?? But the simpliest way to draw was 48.Nd6+ Kg7 (48...Kg6 49.Rg8+ Kh7 50.Rxg3 f2 51.Rf3 f1=Q 52.Rxf1 Rxf1 53.Nxb5 is won for white.) 49.Nf5+ Kf7 50.Nd6+ etc.
Jun-19-08  Antiochus: Do what a problem with 46 Kc3?
Apr-23-13  ariel el luchador: creo que CxP es ganadora 1)T7T+ T2R 2)PXT CxP Y el negro no puede perder con 2 peones de más 46)R3A es una jugada prudente que no pierde
Dec-24-14  poorthylacine: For me, ANTIOCHUS, there is no problem with 46.Kc3!
It would simply have won the game!!
Nov-04-15
Premium Chessgames Member
  dernier loup de T: To give to a participant player any journalistic, organisation, or any other duties while playing the tournament is unaccountable: so for Staunton (1851), Arnous de Rivière (1867), Chigorin (1895/6), and so on... Like a nightmare....
Dec-04-17  Straclonoor: Analysis by Stockfish 111117 64 POPCNT:

1. = (0.08): 47.Re4 Rh2+ 48.Kd3 g2 49.Rg4+ Kf7 50.Nxg2 fxg2 51.Ke3 Ke6 52.Kf2 g1Q+ 53.Kxg1 Rxc2 54.Rg2 Rc1+ 55.Kf2 Rc2+ 56.Kg3 Rc5 57.Rd2 Ke5 58.Kf3 Rc1 59.Ke3 Rh1 60.b3 Rh3+ 61.Ke2 Rh1 62.Kf3 b4 63.Rc2 Kd5 64.Ke3 Re1+ 65.Kd3 Rd1+ 66.Ke2 Rh1 67.Kd2 Rg1 68.Rc4 Rg2+ 69.Kd3 Rxa2

Dec-04-17  heuristic: 37...e4?
37...a4 38.Rg3 Nf6

46.gxf3?
46.Kc3! 46...Rg5 47.Rb8 Ne6

48...Re1?
48...Nd6+ 49.Kg7 Nf5+

48...f2
48...g2! 49.Nd6+ Kf6 50.Ne4+ Kg6

see engine analysis (olga)

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